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Absolute refractive indices of two media P and Q are 1.33 (nP) and 2.52 (nQ) respectively. The speed of light in medium P is 2 x 10^8 m/s.

(a) What would be the speed of light in medium Q (VQ)?

(b) If the angle of incidence for a ray of light travelling from medium P to Q is 0°, then what will be the path of light in the medium Q?

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(a) nP = (Speed of light in vacuum/ speed of light in medium P) 

nq = (Speed of light in vacuum/ speed of light in medium Q)  

Therefore,

nP/nQ = VQ/VP 

= 1.33/2.52 = VQ / 2 x 10^8 

VQ = (1.33 x 2 x 108)/ 2.52 

= 1.056 x 10^8 m/s

(b) the ray will travel undeviated through the medium Q

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