Let the line 4x + y = 4 intersects AB at P(x_{1}, y_{1}) such that AP: PB=k:1

x_{1}= 3k−2/k+1 and y_{1}= 5k−1/k+1

(x_{1}, y_{1}) lies on 4x + y = 4

Therefore, 4(3k−2/k+1)+(5k−1/k+1) = 4

⇒ k = 1

The required ratio is 1:1