Find the value of k for which the quadratic equation 2x² + kx + 3 = 0 has two equal roots.
Solution:
Given equation, 2x² + kx + 3=0Here, a = 2, b = k, c = 3Now, b² - 4ac = 0k² - 4 .2.3=0k² - 24=0k² =24k=±√6.4k=±2√6The value of k so that the equation 2x² + kx + 3=0 has equal roots is 2√6 or -2√6.