Write the discriminant of the quadratic equation 4x2+px+12=0

Question

write the discriminant of the quadratic equation 4x²+px+12=0

Answer 1

Given equation, 4x² - px + 12=0

Here, a = 4, b = -p, c = 12

Now, Discriminant (D) = b² - 4ac
 
                                        = (-P)² - 4.4.12

                                        = P² - 192

Therefore, the discriminant of the given quadratic equation is (p² - 192).