Solution:
Given equation, 9x² + 3kx + 4=0
where, a = 9, b = 3k, c = 4
Since roots are real,
So, b² - 4ac ≥ 0
(3k)² - 4 x 9 x 4 ≥ 0
9k² – 144 ≥ 0
9k² ≥ 144
k² ≥ 144/9
k² ≥ 16
k² ≥ 4²
k ≥ ±4
The value of k so that the equation 9x² + 3kx + 4=0 has real roots is p ≥ 4 or p ≥ - 4.